How to Prepare Rate Analysis for P.C.C. Work

Q. Prepare Rate analysis for a PCC work (1:3:6).

Solⁿ.:-

            Given: - Concrete grade = M10 (1:3:6)  

                                       Take = 10m³ volume for PCC

Add 52% extra for voids to get dry vol^m. of Concrete.

Volume of dry concrete = 1.52×10

                                                  = 15.2 m³

Quantity of cement = (15.2/(1+3+6) ) ×1

                                         = 1.52 m³

      No. of bags             = 1.52×28.5

                                         = 43.32 bags ≅ 44 bags (say)

Quantity of sand = (1.52 ) ×3

                                    = 4.56 m³

Quantity of aggregate = (1.52) ×6

                                              = 9.12 m³

B. Cost of materials

Sr. No.	Material	Unit	Quantity	Rate	Amount
					₹	P.
1.	Cement	Bags	44	350/-	15400	00
2.	Sand	m3	4.56	1000/-	4560	00
3.	Aggregate	m3	9.12	1200/-	10944	00
Total Amount = ₹ 30904.00/-

C. Cost of labours

Sr. No.	Labour	Men (nos.)	Rate	Per(Day)	Amount
					₹	P.
1.	Head Mason	½	400/-	Day	200	00
2.	Mason	1½	350/-	Day	525	00
3.	Male Mazdoor	12	200/-	Day	2400	00
4.	Coolie	18	150/-	Day	2700	00
5.	Bhisti	3	250/-	Day	750	00
6.	T&P	Lump sum	100/-	__	100	00
Total Amount = ₹ 6675.00/-

Total cost = Cost of materials+ Cost of labours

                     = 30904.00+6675.00

Total cost = ₹ 37579.00/-

Add 1.5% Water Charges of total cost

                                              = (1.5/100 ) ×37579

        Water charges = ₹ 563.69/- (say = ₹ 564.00/-)

Add 10% Contractor’s Charges = (10/100 ) ×37579

           Contractor’s Charges = ₹ 3758.90/- (say = ₹ 3759.00/-)

                                                  ____________________________________________

         Grand total = 37579.00+564.00+3759.00

                                     = ₹ 41901.00/-

Rate of work per m³ =   ⇒ ₹ 4190.10/-

Hence Rate of PCC work per m3is ₹ 4190.00/-

To Better Understand Watch this Video